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You signed out in another tab or window. I manually patched it to our system and I'll let you know if I still see the error. Show A. With this explanation, though, you should be able to find the necessary functions in the documentation, or at worst, ask on a relevant IRC channel.

version: 20-Alpha Comment 13 Chris Lumens 2013-11-15 10:02:07 EST *** This bug has been marked as a duplicate of bug 970858 *** Note You need to log in before you can Since you're writing a GUI application, it's easier for you to visualize how to do so, since you already have to write your application within an asynchronous framework. Could you give it a try and tell us if it works for you? asked 4 years ago viewed 2416 times active 1 year ago Upcoming Events 2016 Community Moderator Election ends Nov 22 Visit Chat Related 933Python join, why is it string.join(list) instead of http://stackoverflow.com/questions/482263/beginner-level-python-threading-problems

Python Threading

cannot start() finish the multi-threading perfectly? Sign in to comment Contact GitHub API Training Shop Blog About © 2016 GitHub, Inc. Know of any decent serial modules for Python? –crashsystems Jan 27 '09 at 5:59 pyserial.wiki.sourceforge.net/pySerial In my opinion python with pySerial is your best bet among all languages/technologies if Activity Comments Ascending order - Click to sort in descending order Hide Permalink A.

Is it ethical for a journal to cancel an accepted review request when they have obtained sufficient number of reviews to make a decision? Main hub was shown and after a short moment (or so) bug appeared. It just takes a week or two to find out if the patch really works. You can solve your original problem by using a timeout; telling your GUI framework to call back some function after a delay, and then resetting that delay or starting another delayed

Heino added a comment - Jan 30 2016 03:42:31 PM +00:00 My connection string has two hosts (I have two servers + arbiter): mongodb://user:[email protected],server2/foo?replicaSet=bar&readPreference=primaryPreferred So all of the members are listed, cmdline: /usr/bin/python /sbin/anaconda cmdline_file: initrd=initrd.img inst.stage2=hd:LABEL=Fedora\x2020-Alpha\x20x86_64 quiet BOOT_IMAGE=vmlinuz hashmarkername: anaconda kernel: 3.11.0-300.fc20.x86_64 package: anaconda-20.18-1 product: Fedora reason: RuntimeError: cannot join thread before it is started release: Cannot get release name. Need as many messages as many threads you have OR queue.join() # wait until all tasks done for w in workers: w.continue = False w.put(None) share|improve this answer edited Jun 29 The application seems to run smoothly until suddently at some point (after 20 minutes in example) it terminates with the error thread.error: can't start new thread Any ideas?

type: anaconda version: 20-Alpha-TC2 Potential duplicate: bug 980978 Comment 1 Petr Schindler 2013-08-29 08:21:58 EDT Created attachment 791745 [details] File: anaconda-tb Comment 2 Petr Schindler 2013-08-29 08:22:02 EDT Created attachment 791747 Heino added a comment - Jan 31 2016 09:18:47 AM +00:00 Thanks. Each thread connects to its server to check the server's status. What is the temperature of the brakes after a typical landing?

Python Multithreading

OS is EL6 (Red Hat Enterprise Linux). more hot questions question feed lang-py about us tour help blog chat data legal privacy policy work here advertising info mobile contact us feedback Technology Life / Arts Culture / Recreation Python Threading How do I handle this? You can do it at the very end of your process.

Jesse Jiryu Davis added a comment - Jan 30 2016 02:56:12 PM +00:00 Thanks for the report. Are there continuous functions for which the epsilon-delta property doesn't hold? Skip to content Ignore Learn more Please note that GitHub no longer supports old versions of Firefox. more stack exchange communities company blog Stack Exchange Inbox Reputation and Badges sign up log in tour help Tour Start here for a quick overview of the site Help Center Detailed

I just started my first real job, and have been asked to organize the office party. Format For Printing -XML -Clone This Bug -Top of page First Last Prev Next This bug is not in your last search results. Can I use that to take out what he owes me? Heino Last commenter: Rathi Gnanasekaran Votes: 0 Vote for this issue Watchers: 2 Start watching this issue Dates Created: Jan 30 2016 08:56:55 AM +00:00 Updated: Feb 03 2016 12:00:39 AM

Using a network IO framework (like Twisted) makes it easy to have both parts of your application wait cooperatively instead of competitively, and again alleviates the need for extra threads. Join them; it only takes a minute: Sign up Beginner-level Python threading problems up vote 7 down vote favorite 2 As someone new to GUI development in Python (with pyGTK), I've I changed one method signature and broke 25,000 other classes.

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It just takes a week or two to find out if the patch really works. This incident will be reported Why are LEDs in my home unaffected by voltage drop? more hot questions question feed lang-py about us tour help blog chat data legal privacy policy work here advertising info mobile contact us feedback Technology Life / Arts Culture / Recreation Total distance traveled when visiting all rational numbers On 1941 Dec 7, could Japan have destroyed the Panama Canal instead of Pearl Harbor in a surprise attack?

Reload to refresh your session. Not the answer you're looking for? However, you don't have to do it right after starting the threads. Hide Permalink Kim B.

Join them; it only takes a minute: Sign up python can't start a new thread up vote 1 down vote favorite 1 I am building a multi threading application. Feel free to close this issue for now and I'll let you know if I hit it again in the future. Did you see canonical example from Queue python documentation http://docs.python.org/library/queue.html (bottom of the page)? Try JIRA - bug tracking software for your team.

def long_calculation(param, callback): result = None while True: result = calculate_next_part(param, result) if calculation_is_done(result): break else: yield callback(result) Calling long_calculation will give you a generator object, and calling .next() on the


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