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Cannot Join To Attribute Of Basic Type

Hot Network Questions Is there any known limit for how many dice RPG players are comfortable adding up? more stack exchange communities company blog Stack Exchange Inbox Reputation and Badges sign up log in tour help Tour Start here for a quick overview of the site Help Center Detailed Join is for associations: one-to-one one-to-many many-to-one many-to-many You need to remove this line, as the taxRuleId is already fetched from the database: Join join = taxRoot.join("taxRuleId"); If you want ERROR The requested URL could not be retrieved The following error was encountered while trying to retrieve the URL: http://www.jsourcecode.com/class.php?proj=maven2%5Corg.hibernate%5Chibernate-entitymanager&jar=hibernate-entitymanager-3.6.10.Final&class=org.hibernate.ejb.criteria.BasicPathUsageException Read Error The system returned: (104) Connection reset by peer An navigate here

But with option 3, @Spec(path="firstName", spec=Like.class, [email protected](on="addresses", path="city", spec=In.class) I did not understand why JoinedSpec of city is tied to Spec of firstName. Arduino Uno has 2 crystal? Join us to help others who have the same bug. What am I doing wrong? http://stackoverflow.com/questions/30166806/hibernate-jpa-criteria-basicpathusageexception-cannot-join-to-attribute-of-basi

Generally this means an attempt to de-reference a basic attribute path. @author Steve Ebersole Examples of org.hibernate.ejb.criteria.BasicPathUsageException

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JoinType.INNER.equals(fieldParentJoin.getJoinType()) ) { // This a criteria set by the user (as opposed to the user-limiting criteria) -- it MUST be followed // This means that the join is not optional I'm using hibernate, while I would prefer a JPA solution I'm not adverse to using hibernate specific code. Personal Open source Business Explore Sign up Sign in Pricing Blog Support Search GitHub This repository Watch 16 Star 65 Fork 23 tkaczmarzyk/specification-arg-resolver Code Issues 1 Pull requests 1 Projects So Option 3 might be the way to go.

Accept & Close Home Package Class Method Examples of BasicPathUsageException org.hibernate.ejb.criteria.BasicPathUsageException Represents an incorrect usage of a basic path. more hot questions question feed default about us tour help blog chat data legal privacy policy work here advertising info mobile contact us feedback Technology Life / Arts Culture / Recreation Sign in to comment Contact GitHub API Training Shop Blog About © 2016 GitHub, Inc. I'll asses the options and come back to you!

For example, I would like to retrieve all customers whose city of address matches 'Montreal' in the below entity model. @Entity public class Customer implements Serializable { @Id @GeneratedValue private Long What I need to specify, so that category_id shall be used as relation and join –gangatharan Jun 24 '15 at 13:05 1 You join on "category" not on category_id ... You can vote up the examples you like and your votes will be used in our system to product more good examples. + Save this class to your library Example 1 current community chat Stack Overflow Meta Stack Overflow your communities Sign up or log in to customize your list.

share|improve this answer answered Feb 1 at 11:32 Neil Stockton 5,86031220 add a comment| Your Answer draft saved draft discarded Sign up or log in Sign up using Google Sign https://samebug.io/exceptions/272647/org.hibernate.jpa.criteria.BasicPathUsageException/cannot-join-to-attribute-of-basic-type Why are LEDs in my home unaffected by voltage drop? Essentially, it can't work as you described, because it wouldn't be a valid JPA query -- a join is needed. Should I create multiple maintenance plans to backup more than 200 User databases How do we assign an initial value to a lookup field in sharepoint add in?

super X, Y> assoc, JoinType jt){ if (((SingularAttribute)assoc).getType().getPersistenceType().equals(PersistenceType.BASIC)){ throw new IllegalStateException(ExceptionLocalization.buildMessage("CAN_NOT_JOIN_TO_BASIC")); } Class clazz = assoc.getBindableJavaType(); Fetch join = null; ObjectExpression exp = ((ObjectExpression)this.currentNode).newDerivedExpressionNamed(assoc.getName()); if (jt.equals(JoinType.LEFT)){ exp.doUseOuterJoin(); }else if(jt.equals(JoinType.RIGHT)){ throw http://culturahq.com/cannot-join/cannot-join-windows-2003-domain.html Join them; it only takes a minute: Sign up BasicPathUsageException: Cannot join to attribute of basic type up vote 1 down vote favorite I am using Java 8 with JPA (Hibernate asked 1 year ago viewed 881 times Upcoming Events 2016 Community Moderator Election ends Nov 22 Related 455What's the difference between JPA and Hibernate?1JPA - Issue using Criteria inner join table Automated exception search integrated into your IDE Test Samebug Integration for IntelliJ IDEA 0 mark Exception is thrown when trying to JOIN embedded attribute in Criteria API.

Why is looping over find's output bad practice? Join them; it only takes a minute: Sign up JPA Criteria with Join against self with primitive types up vote 0 down vote favorite I have an entity that looks like How to react? his comment is here You could add another from() class, and add a where clause. –Neil Stockton Feb 1 at 11:09 Thanks, I hoped I had missed something but guess not.

This incident will be reported Where do I drop off a foot passenger in Calais (P&O)? specification-arg-resolver owner tkaczmarzyk commented May 16, 2016 • edited @JoinFetch adds JPA fetch join (which just initializes collections, but is not used for filtering). If you want to add an answer I'll accept it. –vickirk Feb 1 at 11:21 add a comment| 1 Answer 1 active oldest votes up vote 1 down vote accepted You

super X, Y> collection, JoinType jt) { if ( jt.equals( JoinType.RIGHT ) ) { throw new UnsupportedOperationException( "RIGHT JOIN not supported" ); } // TODO : runtime check that the attribute

Why does the Minus World exist? Is there any known limit for how many dice RPG players are comfortable adding up? Advisor professor asks for my dissertation research source-code I changed one method signature and broke 25,000 other classes. Take a tour to get the most out of Samebug.

more stack exchange communities company blog Stack Exchange Inbox Reputation and Badges sign up log in tour help Tour Start here for a quick overview of the site Help Center Detailed more hot questions question feed lang-java about us tour help blog chat data legal privacy policy work here advertising info mobile contact us feedback Technology Life / Arts Culture / Recreation having the following entity: {quote} @Entity public class Client implements Serializable { @Id public int id; @Embedded public Name name; } @Embeddable public class Name implements Serializable { @Column public String weblink getCommonPredicates(filter, cb, root, predicates); // Add predicates for attr values addAttributePredicates(cb, predicates, filter.getAttributeFilters()); criteria.where(predicates.toArray(new Predicate[predicates.size()])); TypedQuery query = entityManager.createQuery(criteria); List resultsList = query.getResultList(); This however gives me the error: org.hibernate.jpa.criteria.BasicPathUsageException: Cannot

This site uses cookies, as explained in our cookie policy. specification-arg-resolver owner tkaczmarzyk commented May 16, 2016 Update, distinct is not a problem :) ekalabs commented May 17, 2016 • edited Nice to hear from you on the options and explanation. Can I use that to take out what he owes me? Employee - employee_category - category model (Employee.java): @ManyToMany(cascade = CascadeType.ALL, fetch=FetchType.EAGER) @JoinTable ( name="employee_category", joinColumns={ @JoinColumn(name="EMP_ID", referencedColumnName="ID") }, inverseJoinColumns={ @JoinColumn(name="CAT_ID", referencedColumnName="ID") } ) private Set categories; model (Category.java): @Id private String

There is one column same in both table i.e TAX_RULE_ID. Automated exception search integrated into your IDE Test Samebug Integration for IntelliJ IDEA Root Cause Analysis org.hibernate.jpa.criteria.BasicPathUsageException Cannot join to attribute of basic type at org.hibernate.jpa.criteria.path.AbstractFromImpl.constructJoin(AbstractFromImpl.java:270) at org.hibernate.jpa.criteria.path.AbstractFromImpl.join() org.hibernate.jpa AbstractFromImpl.join org.hibernate.jpa.criteria.path.AbstractFromImpl.join(AbstractFromImpl.java:263) How Did The Dred Scott Decision Contribute to the Civil War? All rights reserved.

Browse other questions tagged java oracle hibernate jpa hibernate-criteria or ask your own question. Are there continuous functions for which the epsilon-delta property doesn't hold? Your cache administrator is webmaster. Why did Michael Corleone not forgive his brother Fredo?

You signed out in another tab or window. Wrong way on a bike path? In case when only the latter is required, I would allow using just @JoinedSpec, without @Spec wrapper. having the following entity: {quote} @Entity public class Client implements Serializable { @Id public int id; @Embedded public Name name; } @Embeddable public class Name implements Serializable { @Column public String

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